(v+6)^2=2v^+10v+28

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Solution for (v+6)^2=2v^+10v+28 equation: 



(v+6)^2=2v^+10v+28

We move all terms to the left:

(v+6)^2-(2v^+10v+28)=0

We get rid of parentheses

(v+6)^2-2v^-10v-28=0

We add all the numbers together, and all the variables

-12v+(v+6)^2-28=0

We move all terms containing v to the left, all other terms to the right

-12v+(v+6)^2=28

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